Jawaban:
f(x) = ax² + bx
f(1) = a(1)² + b(1) = -1
a + b = -1 ... (i)
f(2) = a(2)² + b(2) = 2
4a + 2b = 2 ... (ii)
a + b = -1 |× 2| 2a + 2b = -2
4a + 2b = 2 |× 1 | 4a + 2b = 2 (-)
-2a = -4
a = -4/-2
a = 2
a + b = -1
(2) + b = -1
2 + b = -1
b = -1 - 2
b = -3
Maka rumus fungsi f(x)
f(x) = (2)x² + (-3)x
f(x) = 2x² - 3x
Maka jawabannya adalah f(x) = 2x² - 3x
'조슈아' (Svt)
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Jawaban:
Penyelesaian :
Mencari rumus fungsi
f(x) = ax² + bx
f(1) = a(1)² + b(1) = -1
a + b = -1 ... (i)
f(2) = a(2)² + b(2) = 2
4a + 2b = 2 ... (ii)
a + b = -1 |× 2| 2a + 2b = -2
4a + 2b = 2 |× 1 | 4a + 2b = 2 (-)
-2a = -4
a = -4/-2
a = 2
a + b = -1
(2) + b = -1
2 + b = -1
b = -1 - 2
b = -3
Maka rumus fungsi f(x)
f(x) = ax² + bx
f(x) = (2)x² + (-3)x
f(x) = 2x² - 3x
Maka jawabannya adalah f(x) = 2x² - 3x
'조슈아' (Svt)