Odpowiedź:
z.22
a = 3 n + 2 r = 2
więc
a³ = ( 3 n + 2)³ = 27 n³ + 3*9 n²*2 + 3*3*2n*4 + 8 =
= 27 n³ + 54 n² + 36 n + 8 = 3*(9 n³ + 18 n² + 12 n + 2 ) + 2
r =2
==========
z.23
{ 1,2,3,4,5,6,7,8 }
I omega I = 8² = 64
A = { 11,18,27,38,51,66,83 }
I A I = 7
P( A ) = [tex]\frac{7}{64}[/tex]
=============
[tex]3^2 + 2 = 11, 4^2 + 2 = 18, 5^2 + 2 = 27, 6^2 + 2 = 38,7^2 + 2 = 51, 8^2 + 2 = 66, 9^2 + 2 = 83[/tex]
------------------------------------------------------------------------------------------------------
Szczegółowe wyjaśnienie:
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
z.22
a = 3 n + 2 r = 2
więc
a³ = ( 3 n + 2)³ = 27 n³ + 3*9 n²*2 + 3*3*2n*4 + 8 =
= 27 n³ + 54 n² + 36 n + 8 = 3*(9 n³ + 18 n² + 12 n + 2 ) + 2
r =2
==========
z.23
{ 1,2,3,4,5,6,7,8 }
I omega I = 8² = 64
A = { 11,18,27,38,51,66,83 }
I A I = 7
P( A ) = [tex]\frac{7}{64}[/tex]
=============
[tex]3^2 + 2 = 11, 4^2 + 2 = 18, 5^2 + 2 = 27, 6^2 + 2 = 38,7^2 + 2 = 51, 8^2 + 2 = 66, 9^2 + 2 = 83[/tex]
------------------------------------------------------------------------------------------------------
Szczegółowe wyjaśnienie: