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-5x(x+2)=0
x=0 lub x=-2
x∈(-2,0)
2]
(5x+6)/x=x /*x załozenie ; x≠0
5x+6=x²
x²-5x-6=0
Δ=b²-4ac=25+24=49 √Δ=7
x1=[-b-√Δ]/2a=[5-7]/2=-1
x2=[-b+√Δ]/2a=[5+7]/2=6