Question

Resuelvan el siguiente sistema de ecuaciones lineales (grafica)
X/2 + y/3 = 4
X/3 + y = 1

Answer 1

X/2  + Y/3 = 4

[3X + 2Y]/6 = 4

3X + 2Y = 24;

X/3 + Y = 1

[X + 3Y]/3 = 1

X + 3Y = 3;

3X + 2Y = 24;  3X = 24 - 2Y;   X = 8 - (2/3)Y

X + 3Y = 3;  8 - (2/3)Y + 3Y = 3

3Y - (2/3)Y = -5

9Y/3 - 2Y/3 = -5

7Y/3 = -5;   7Y = -15;   Y = -15/7

X = 8 - (2/3)(-15/7) = 8 + 10/7 = 56/7 + 10/7 = 66/7

(66/7 , -15/7)

La solucion es X = 66/7;  Y = -15/7

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