[tex] \frac{1}{2} (x + 1) = \frac{1}{3}(x + 8)[/tex]
[tex] \frac{x + 1}{2} = \frac{x + 8}{3} [/tex]
[tex]3x + 3 = 2x + 16[/tex]
[tex]x = 13[/tex]
Respuesta:
[tex]\frac{1}{2}\left(x+1\right)=\frac{1}{3}\left(x+8\right)[/tex]
[tex]\mathrm{Resolvemos:}[/tex]
[tex]\frac{1}{2}\left(x+1\right)=\frac{1}{2}x+\frac{1}{2}[/tex]
[tex]\frac{1}{3}\left(x+8\right)=\frac{1}{3}x+\frac{8}{3}[/tex]
[tex]\frac{1}{2}x+\frac{1}{2}=\frac{1}{3}x+\frac{8}{3}[/tex]
[tex]\frac{1}{2}x=\frac{13}{6}+\frac{1}{3}x[/tex]
[tex]\frac{1}{6}x=\frac{13}{6}[/tex]
[tex]\mathrm{Multiplicamos \ por \ 6:}[/tex]
[tex]6\cdot \frac{1}{6}x=\frac{13\cdot \:6}{6}[/tex]
Solución
[tex]\frac{13\cdot \:6}{6}=\frac{78}{6}=13[/tex]
[tex]\boxed{\text{x}=13}[/tex]
Saludos...
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[tex] \frac{1}{2} (x + 1) = \frac{1}{3}(x + 8)[/tex]
[tex] \frac{x + 1}{2} = \frac{x + 8}{3} [/tex]
[tex]3x + 3 = 2x + 16[/tex]
[tex]x = 13[/tex]
Respuesta:
[tex]\frac{1}{2}\left(x+1\right)=\frac{1}{3}\left(x+8\right)[/tex]
[tex]\mathrm{Resolvemos:}[/tex]
[tex]\frac{1}{2}\left(x+1\right)=\frac{1}{2}x+\frac{1}{2}[/tex]
[tex]\frac{1}{3}\left(x+8\right)=\frac{1}{3}x+\frac{8}{3}[/tex]
[tex]\frac{1}{2}x+\frac{1}{2}=\frac{1}{3}x+\frac{8}{3}[/tex]
[tex]\frac{1}{2}x=\frac{13}{6}+\frac{1}{3}x[/tex]
[tex]\frac{1}{6}x=\frac{13}{6}[/tex]
[tex]\mathrm{Multiplicamos \ por \ 6:}[/tex]
[tex]6\cdot \frac{1}{6}x=\frac{13\cdot \:6}{6}[/tex]
Solución
[tex]\frac{13\cdot \:6}{6}=\frac{78}{6}=13[/tex]
[tex]\boxed{\text{x}=13}[/tex]
Saludos...