Zapisz w jak najprostrzej postaci
a): (x+4)+(2x-6)=
b); -(2y+3x)+(-4y+2x+1)
c): -(x-2xy)-(4x+xy)+(xy-1)
d): (x^2+2x+1)-(x^2-4x+3)
,,^-potega
zapisz w postaci sumy algebraicznej
a)(2a+b)*c-(2ac-bc+1)
b) 5(x-z)+2(z-x)
c)2x^2(x-5)-3x(x^2-3x+5)
d)6(a^2+b+1/3)-6(a^2-1/2)-3(b+1/3)
^-Potęga
1/3-ułamki)
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a).(x+4)+(2x-6)=x+4+2x-6=3x-2
b).-(2y+3x)+(-4y+2x+1)=-2y-3x-4y+2x+1=-x-6y+1
c).-(x-2xy)-(4x+xy)+(xy-1)=-x+2xy-4x-xy+xy-1=-5x+2xy-1
d).(x^2+2x+1)-(x^2-4x+3)=x^2+2x+1-x^2+4x-3=6x-2
a).(2a+b)*c-(2ac-bc+1)=2ac+bc-2ac+bc-1=2bc-1
b).5(x-z)+2(z-x)=5x-5z+2z-2x=3x-3z
c).2x^2(x-5)-3x(x^2-3x+5)=2x^3-10x^2-3x^3+9x^2-15x=-x^3-x^2-15x
d).6(a^2+b+1/3)-6(a^2-1/2)-3(b+1/3)=6a^2+6b+2-6a^2+3-3b-1=3b+4