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Verified answer
KINEMATIKA• persamaan gerak
θ₀ = ⅔ rad
θ(2) = ___?
persamaan kecepatan sudut
ω (t) = (2t² + 3t + 4) rad/s
persamaan posisi sudut
θ(t) = ∫ ω dt + θ₀
θ(t) = ∫ (2t² + 3t + 4) dt + ⅔
θ(t) = (⅔t³ + ³/₂t² + 4t + ⅔) rad
untuk t = 2 s
θ(2) = ⅔•2³ + ³/₂•2² + 4•2 + ⅔
θ(2) = ¹⁶/₃ + 6 + 8 + ⅔
θ(2) = ¹⁸/₃ + 14
θ(2) = 6 + 14
θ(2) = 20 rad ← jwb
Kedudukan sudut titik tersebut 20 rad ✓