oblicz n-ty wyraz ciagu geometrycznego gdzie a1 = 1/3 , q= pierwiastek kwadratowy z 3 , n=10
an=a1*q do n-1
a10=1/3*(√3) do 10-1
a10=1/3*(√3)⁹
a10=1/3*81√3
a10=27√3
licze na naj
[/tex]
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an=a1*q do n-1
a10=1/3*(√3) do 10-1
a10=1/3*(√3)⁹
a10=1/3*81√3
a10=27√3
licze na naj
[/tex]