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y - 3 = - 1/3 (x - 1) ......... kedua ruas kalikan dengan 3
3y - 9 = - 1 (x - 1)
3y - 9 = - x + 1
x +3y - 9 - 1 = 0
x +3y - 10 = 0
m=-1/3
(y-y1) = m (x-x1)
(y-3) = -1/3 (x-1)
(y-3) 3 = -1(x-1)
3y -9 = -x+1
x +3y -10 = 0