zad20
Trójkat A'B'C', ktorego pole wynosi 30cm2, jest podobny do trojkata ABC w skali k= 5/3. Oblicz pole trojkata ABC.
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dane:
PΔ A"B"C"=30cm²
k=5/3
szukane:
PΔ ABC=?
PΔA"B"C" /PΔ ABC=k²
30cm² /PΔABC=(5/3)²
30cm² /PΔABC=25/9
PΔABC=30cm²·9/25
PΔABC=10,8cm²