Respuesta:
A) 334/105
B) -49/6
C) -343/3
Espero te ayude :)
a) [tex]-\frac{4}{14}+3\frac{1}{2}-\frac{2}{20}\cdot \frac{1}{3}[/tex]
[tex]3\frac{1}{2}=\frac{7}{2}[/tex]
[tex]=-\frac{4}{14}+\frac{7}{2}-\frac{2}{20}\cdot \frac{1}{3}[/tex]
[tex]-\frac{2}{20}\cdot \frac{1}{3}=-\frac{1}{30}[/tex]
[tex]=-\frac{4}{14}+\frac{7}{2}-\frac{1}{30}[/tex]
[tex]-\frac{4}{14}:\frac{2}{7}[/tex]
[tex]=-\frac{2}{7}+\frac{7}{2}-\frac{1}{30}[/tex]
[tex]=-\frac{60}{210}+\frac{735}{210}-\frac{7}{210}[/tex]
[tex]=\frac{-60+735-7}{210}[/tex]
[tex]-60+735-7=668[/tex]
[tex]=\frac{668}{210}[/tex]
[tex]\frac{668}{210}:\frac{334}{105}[/tex]
[tex]\frac{334}{105}=3\frac{19}{105}[/tex]
[tex]=3\frac{19}{105}[/tex]
b)[tex]-\frac{6}{5}\cdot \:10+\frac{15}{10}+2\frac{1}{3}[/tex]
[tex]2\frac{1}{3}=\frac{7}{3}[/tex]
[tex]=-\frac{6}{5}\cdot \:10+\frac{15}{10}+\frac{7}{3}[/tex]
[tex]\frac{15}{10}=\frac{3}{2}[/tex]
[tex]=-\frac{6}{5}\cdot \:10+\frac{3}{2}+\frac{7}{3}[/tex]
[tex]-\frac{6}{5}\cdot \:10:-12[/tex]
[tex]=-12+\frac{3}{2}+\frac{7}{3}[/tex]
[tex]=-\frac{49}{6}[/tex]
c)[tex]-109-4\cdot \left(\frac{2}{3}+1\right)+1\frac{1}{3}[/tex]
[tex]1\frac{1}{3}=\frac{4}{3}[/tex]
[tex]=-109-4\cdot \left(\frac{2}{3}+1\right)+\frac{4}{3}[/tex]
[tex]\left(\frac{2}{3}+1\right):\frac{5}{3}[/tex]
[tex]=-109-4\cdot \frac{5}{3}+\frac{4}{3}[/tex]
[tex]4\cdot \frac{5}{3}:\frac{20}{3}[/tex]
[tex]=-109-\frac{20}{3}+\frac{4}{3}[/tex]
[tex]=-\frac{343}{3}[/tex]
[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
A) 334/105
B) -49/6
C) -343/3
Espero te ayude :)
Verified answer
a) [tex]-\frac{4}{14}+3\frac{1}{2}-\frac{2}{20}\cdot \frac{1}{3}[/tex]
[tex]3\frac{1}{2}=\frac{7}{2}[/tex]
[tex]=-\frac{4}{14}+\frac{7}{2}-\frac{2}{20}\cdot \frac{1}{3}[/tex]
[tex]-\frac{2}{20}\cdot \frac{1}{3}=-\frac{1}{30}[/tex]
[tex]=-\frac{4}{14}+\frac{7}{2}-\frac{1}{30}[/tex]
[tex]-\frac{4}{14}:\frac{2}{7}[/tex]
[tex]=-\frac{2}{7}+\frac{7}{2}-\frac{1}{30}[/tex]
[tex]=-\frac{60}{210}+\frac{735}{210}-\frac{7}{210}[/tex]
[tex]=\frac{-60+735-7}{210}[/tex]
[tex]-60+735-7=668[/tex]
[tex]=\frac{668}{210}[/tex]
[tex]\frac{668}{210}:\frac{334}{105}[/tex]
[tex]\frac{334}{105}=3\frac{19}{105}[/tex]
[tex]=3\frac{19}{105}[/tex]
b)[tex]-\frac{6}{5}\cdot \:10+\frac{15}{10}+2\frac{1}{3}[/tex]
[tex]2\frac{1}{3}=\frac{7}{3}[/tex]
[tex]=-\frac{6}{5}\cdot \:10+\frac{15}{10}+\frac{7}{3}[/tex]
[tex]\frac{15}{10}=\frac{3}{2}[/tex]
[tex]=-\frac{6}{5}\cdot \:10+\frac{3}{2}+\frac{7}{3}[/tex]
[tex]-\frac{6}{5}\cdot \:10:-12[/tex]
[tex]=-12+\frac{3}{2}+\frac{7}{3}[/tex]
[tex]=-\frac{49}{6}[/tex]
c)[tex]-109-4\cdot \left(\frac{2}{3}+1\right)+1\frac{1}{3}[/tex]
[tex]1\frac{1}{3}=\frac{4}{3}[/tex]
[tex]=-109-4\cdot \left(\frac{2}{3}+1\right)+\frac{4}{3}[/tex]
[tex]\left(\frac{2}{3}+1\right):\frac{5}{3}[/tex]
[tex]=-109-4\cdot \frac{5}{3}+\frac{4}{3}[/tex]
[tex]4\cdot \frac{5}{3}:\frac{20}{3}[/tex]
[tex]=-109-\frac{20}{3}+\frac{4}{3}[/tex]
[tex]=-\frac{343}{3}[/tex]
[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]