Question

Jika tan(a+b)=1/2 dan tan(b+c)=1/3, maka nilai tan (a-c) = ?

Answer 1

A - c = (a + b) - (b + c)
tan (a - c) = tan ( (a+b) - (b+c) )
misalkan a+b = x dan b+c = y
tan (x - y) = (tan x  - tan y)/(1 + tanx.tany)
tan (x - y) = (1/2 - 1/3) / (1 + 1/2.1/3)
tan (x - y) = (1/6) / (7/6)
tan (x - y) = 1/7
tan (a - c) = 1/7.