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pq = 2,qr=2 akar 10
tan R =1/3
nilai cos Q =?
jawab
tan R = 1/3
depan/samping = 1/3
PQ/PR =1/3
PQ/6 = 1/3
3PQ = 6
PQ = 6/3=2
QR² = PQ²+PR²
QR²= 2²+6²
QR =√40
QR = √4.10
QR = 2√10
cos Q = samping /miring
cos Q = PQ/QR
cos Q = 2/2√10
cos Q = 1/√10 atau √10/10