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diket :
3^2x + 3^-2x = 98
tentukan nilai 3^x + 3^-x = .... ?
misal
y = 3^x + 3^-x
kuadratkan kedua ruas, get
y^2 = (3^x + 3^-x)^2
y^2 = 3^2x + 2 + 3^-2x
y^2 = 98 + 2
y^2 = 100
y = +- √100
y = +- 10