3 krotkie zadania z matmy. licze na pomoc z gory dzieki. potrzebne na dzisiaj !!!! ratunku
10
2x³+3x²-4x-6=x²(2x+3)-2(2x+3)=(2x+3)(x²-2)=(2x+3)(x-√2)(x+√2)
x₁= - 3/2
x₂=√2
x₃= -√2
x₁+x₂+x₃= -3/2+√2-√2= -3/2
11
4x-y-5=0
y=4x-5 [4,5] y=f(x-p)+q wzór funkcji po przesunięciu o wektor [p,q]
y=4(x-4) - 5 +5
y=4x - 16
y=0
4x-16=0
4x=16
x=4 (4,0)
12
a=log₃√₃ 1/27
3√3)^a=1/27
3^3/2a=3⁻³
3/2a=-3 /:3/2
a= -3·⅔= -2
b=log1/2 (4√8)
½)^b=4√8
½)^b=2²·2^3/2
2^(-b)=2^(2+3/2)
-b=3½
b= -3½
c=log₄½√2
4^c=½√2
2^2c=2⁻¹·2^½
2^2c=2^(-½)
2c= - ½ /:2
c= - ¼
c= -¼,a= -2,b= -3½
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10
2x³+3x²-4x-6=x²(2x+3)-2(2x+3)=(2x+3)(x²-2)=(2x+3)(x-√2)(x+√2)
x₁= - 3/2
x₂=√2
x₃= -√2
x₁+x₂+x₃= -3/2+√2-√2= -3/2
11
4x-y-5=0
y=4x-5 [4,5] y=f(x-p)+q wzór funkcji po przesunięciu o wektor [p,q]
y=4(x-4) - 5 +5
y=4x - 16
y=0
4x-16=0
4x=16
x=4 (4,0)
12
a=log₃√₃ 1/27
3√3)^a=1/27
3^3/2a=3⁻³
3/2a=-3 /:3/2
a= -3·⅔= -2
b=log1/2 (4√8)
½)^b=4√8
½)^b=2²·2^3/2
2^(-b)=2^(2+3/2)
-b=3½
b= -3½
c=log₄½√2
4^c=½√2
2^2c=2⁻¹·2^½
2^2c=2^(-½)
2c= - ½ /:2
c= - ¼
c= -¼,a= -2,b= -3½