Question

Diketahui A dan B sudut lancip, tan A = 5/12 dan cot B = 4/3 , Hitunglah :
a. sin A cos B + cos A sin B
b. cos A cos B - sin A sin B

tolong dijawab yooo;;)

Answer 1

Tan A = depan/samping = 5/12
sin A = 5/13
cos A = 12/13

cot B = samping/depan = 4/3
cos B = 4/5
sin B = 3/5

a) sin A cos B + cos A sin B = 5/13 x 4/5 + 12/13 x 3/5
= 20/65 + 36/35
= 56/65
b) cos A cos B - sin A sin B = 12/13 x 4/5 - 5/13 x 3/5
= 48/65 - 15/65
= 33/65