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Integral Tak Tentujika ∫ a xⁿ dx = a/(n+1) xⁿ⁺¹ + c
1. ∫x³ dx = 1/(3+1) x³⁺¹ + c = ¹/₄ x⁴ + c
2. ∫ 8x dx = 8/(1+1) x¹⁺¹ + c = 8/2 x² = 4x² + c
3. ∫15 x⁴ dx = 15/(4+1) x⁴⁺¹ + c = 15/5 x⁵ = 3x⁵ + c
4. ∫ 5x⁻³ dx = 5/(-3+1) x⁻³⁺¹ + c = -5/-2 x⁻² + c = - 5/2 x⁻² + c
5. ∫ 7x²/³ dx = 7/(2/3+ 1) x²/³ ⁺¹ + c = 7/(5/3) x⁵/³ +c = 21/5 x⁵/³ + c
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Insyaallah semoga dapat mmbantu dan barokallah