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U1 ∙ 2µF = U2 ∙ 5µF
Z II prawa Kirchhoffa:
U1+U2 = 200V -> U1 = 200V-U2
(200V-U2) ∙ 2µF = U2 ∙ 5µF
400 µC = U2 ∙ 7µF
U2 = 400/7 V = 57,14 V
U1 = 200V - 142,86 V = 142,86 V