Dana jest liczba x= 63 do kwadratu * (1/3) do potęgi 4. Wtedy:
x = 7 do kwadratu
B. x = 7 -2 do kwadratu
C. x = 3 do potęgi 8 ⋅7 do potęgi 2
D. x = 3⋅7
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x = 63^2 *(1/3)^4
x =(9 *7)^2 *1/81
x = 9^2 * 7^2 *1/81
x = 81 * 7^2 *1/81
x =7^2
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Odp.A. x =7^2 (7 do kwadratu)