Question

Oblicz, jakim procentem liczby a jest liczba b, jeżeli :

a=(1/3)do potęgi -1 * 9do potęgi -1 +(1/2)do potęgi -1 * 4do potęgi -1, b= 6do potęgi -3 * (1/6) do potęgi -3 / (2/3) do potęgi -3 .

Pilne!!

Answer 1

a = (1/3)^(-1) * 9^(-1) *(1/2)*(-1) * 4^(-1) =

  = 3*(1/9) *2*(1/4) = (3/9)*(2/4) = (1/3)*(1/2) = 1/6

b = 6^(-3) *(1/6)^(-3) - 3/[ (2/3)^(-3) ] =

= [ 1/6^3] * 6^3 - 3 / [(3/2)^3] =

= [ (1/6)*6]^3 - 3 /[27/8] =

= 1^3 - 3 *[8/27] = 1 - 8/9 = 9/9 - 8/9 = 1/9

a = 1/6

b = 1/9

b/a = (1/9) : ( 1/6) = (1/9)*(6/1) = 6/9 = 2/3

b/a = 2/3 = 0,6666666666666... = 0,666(6) = 66,(6 ) % = około 66,7 %

Answer 2