Question

zad 13 str 61 2 gimnazjum operon

i) 14/3-√2

j)4/√6 - 2

k) √3/2 + √3

l) 6/√5 + √2

m)3√3/2√3 - 3

n)√7 - 2/√7 +2

zad 1 str 60

oblicz:

a)√5 4/9*|√4 do potegi -1 +(2 4/5) do potegi -1|

b)√7 1/9 -√1,44*1 2/3) do potegi 2

chce całe rozwiązania

Answer 1

       

i)14/3-√2  *  3+√2/3+√2 =42+14√2 / (9-2)=

=7(6+2√2)/7= 6+2√2

 

j)4/√6-2  *  √6+2/√6+2 =4√6+8 / (6-4)=

=2(2√6+4)/2=2√6+4

 

k)√3/2+√3 * 2-√3/2-√3 =2√3-3/(4-3)=2√3-3

 

l)6/√5+√2  *  √5-√2/√5-√2=6√5-6√2/3=2√5 - 2√2=2(√5-√2)

 

m)3√3/2√3-3  *  2√3+3/2√3+3 =18+9√3 /(12-9)=

=9(2+√3)/3 = 3(2+√3)

 

n)√7-2/√7+2  *  √7-2/√7-2 =7-4√7+4 / (7-4)=

=11-4√7 / 3

 

a)=√49/9*|1/2+5/14|=7/3*| 7/14 +5/14|=7/3*12/14=7/3 * 6/7 = 2

 

b) =(√64/9 -1,2 *5/3)²=(8/3 - 12/10 *5/3)²=(8/3 - 2)²=(8/3 - 6/3)²=(2/3)²=4/9