Question

Oblicz stosujac prawa działan na potegach:

a) 8 do - 4 potęgi razy 8 do 5 potegi=

b)(2/3) do - 2 potęgi : (2/3) do 4 potęgi

c)[ (4/3) do - 2 potęgi] do 2 potęgi : (4/3) do 6 potęgi

d) (2,4) do - 3 potęgi : (0,6) do - 3 potęgi

Prosze o odpowiedz;))

Answer 1

a)8^-4 *  8^5 = 8^(-4+5)=8^1=8

b)(2/3)^-2 : (2/3)^4 = (2/3)^(-2-4) = (2/3)^-6 = (3/2)^6 = 729/64=11  25/64

c)[(4/3)^-2]^2 : (4/3)^6 = (4/3)^-4 : (4/3)^6 = (4/3)^(-4-6) = (4/3)^-10 =

            = (3/4)^10 =59049/1048576≈0,056

d) (2,4)^-3 : (0,6)^-3 = (2,4:0,6)^-3 = 4^-3 = (1/4)^-3 = 1/64

Answer 2

a)   8⁻⁴·8⁵ = 8⁻⁴⁺⁵ = 8¹ = 8

b)   (⅔)⁻²÷(⅔)⁴ = (⅔)⁻²⁻⁴ = (⅔)⁻⁶ = (3/2)⁶ = 729/64

c)   [(4/3)⁻²]²÷(4/3)⁶ = (4/3)⁻⁴÷(4/3)⁶ = (4/3)⁻⁴⁻⁶ = (4/3)⁻¹⁰ = (3/4)¹⁰ = 59049/1048576

d)   (2,4)⁻³÷(0,6)⁻³ = (2,4/0,6)⁻³ = 4⁻³ = (1/4)³ = 1/64