Question

Oblicz do potęgi:
a) 5 do 3, 2 do 5, (-3) do 4, (-4) do 3
b) 0 do 6, (1 3/7) do 1, (-1) do 4, (-10) do 0
c) (1/2) do 5, (-3/5) do 4, 0,2 do 6, (-0,03) do 3
d) (-1/1) do 2, (1 1/4) do 3, (-2 1/5) do 3, 1,3 do 2
e) 2/3 do 3, (-3)/2 do 2, 2/3 do 3, -5/(-3) do 3 i do 2

Answer 1

a)
5^3 = 5*5*5 = 125
2^5 = 2*2*2*2*2 = 32
(-3)^4 = (-3)*(-3)*(-3)*(-3) = 81
(-4)^3 = (-4)*(-4)*(-4) = -64

b)
0^6 = 0
(1 3/7)^1 = 1 3/7
(-1)^4 = (-1)*(-1)*(-1)*(-1) = 1
(-10)^0 = 0

c)
(1/2)^5 = (1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/32
(-3/5)^4 = (-3/5)*(-3/5)*(-3/5)*(-3/5) = 81/625
0,2^6 = 0,2*0,2*0,2*0,2*0,2*0,2 = 0,000064
(-0,03)^3 = (-0,03)*(-0,03)*(-0,03) = -0,000027

d)
(-1/1)^2 = (-1/1)*(-1/1) = 1,21
(1 1/4)^3 = (5/4)^3 = (5/4)*(5/4)*(5/4) = 125/64
(-2 1/5)^3 = (-11/5)^3 = (-11/5)*(-11/5)*(-11/5) =-1331/125
1,3^2 = 1,3*1,3 = 1,69

e)
2/3^3 = 2/3*2/3*2/3 = 8/27
(-3)/2^2 = (-3)/2*(-3)/2*(-3)/2= -27/8
2/3^3 = 2/3*2/3*2/3 = 8/27
-5^3/(-3)^2 = -5*-5*-5 / (-3)*(-3) = -125/9


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