Persamaan garis yg melalui titik (2,-3) dengan gradien 1/3 adalah ...... a.-11+x+3y=0 b.-11+x-3y=0 c.-11+x-y=0 d. 11+3x+3y=0 e. 11+3x-3y=0 pakai cara ya........ tolong bantuin
3518lon
Y = mx +c y = 1/3x +c => substitusi x dan y -3 = 1/3 . 2 + c -3 = 2/3 +c c = 3+ 2/3 pers grs : y = 1/3x+11/3 => dikali 3 3y = x+11 3y-x-11 = 0
y = 1/3x +c => substitusi x dan y
-3 = 1/3 . 2 + c
-3 = 2/3 +c
c = 3+ 2/3
pers grs : y = 1/3x+11/3 => dikali 3
3y = x+11
3y-x-11 = 0