Respuesta:
Explicación paso a paso:
[tex]Tenemos\\1) (-2.1).....un..punto\\2) m=-2/3\\\\sabemos\\y=mx+b\\tambien\\y-y_{0}=m(x-x_{0} ) \\y_{0} =1\\x_{0}=-2\\\\m=-2/3\\Reemplazando\\\\\\y-1=\frac{-2}{3} .(x-(-2))\\y-1=\frac{-2}{3} .(x+2)\\y-1=\frac{-2x-4}{3} \\y=\frac{-2x-4}{3}+1\\y=\frac{-2x-4+3}{3}\\y= \frac{-2x-1}{3}\\y=\frac{-2x}{3} -\frac{1}{3}[/tex]
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Respuesta:
Explicación paso a paso:
[tex]Tenemos\\1) (-2.1).....un..punto\\2) m=-2/3\\\\sabemos\\y=mx+b\\tambien\\y-y_{0}=m(x-x_{0} ) \\y_{0} =1\\x_{0}=-2\\\\m=-2/3\\Reemplazando\\\\\\y-1=\frac{-2}{3} .(x-(-2))\\y-1=\frac{-2}{3} .(x+2)\\y-1=\frac{-2x-4}{3} \\y=\frac{-2x-4}{3}+1\\y=\frac{-2x-4+3}{3}\\y= \frac{-2x-1}{3}\\y=\frac{-2x}{3} -\frac{1}{3}[/tex]