Oblicz najprostszym sposobem, czyli ma być jak najłatwiej za zastosowaniem wzoru wynik wychodzi -63 przynajmniej tak pisze w odpowiedziach. ^- do potęgi /-kreska ułamkowa.
[(2/3)^-6 - (1/3)^-6] x 1,5^-6 = ?
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[(2/3)^-6 - (1/3)^-6] x 1,5^-6 =
(2/3)^(-6) x 1,5^(-6) - (1/3)^(-6) x 1,5^(-6) =
(2/3 * 1,5)^(-6) - (1/3 * 1,5)^(-6) =
(2/3 * 3/2)^(-6) - (1/3 * 3/2)^(-6) =
1^(-6) - (1/2)^(-6) = 1 - 2^6 = 1 - 64 = -63
[(2/3)⁻⁶ - (1/3)⁻⁶] × 1,5⁻⁶ =
= [(2/3)⁻⁶ - (1/3)⁻⁶] × (3/2)⁻⁶ =
= (2/3)⁻⁶ × (3/2)⁻⁶ - (1/3)⁻⁶ × (3/2)⁻⁶ =
= (3/2)⁶ × (3/2)⁻⁶ - 3⁶ × (3/2)⁻⁶ =
= (3/2)⁶⁻⁶ - 3⁶ × 2⁶ × 3⁻⁶ =
= (3/2)⁰ - 2⁶ × 3⁶⁻⁶ =
= 1 - 2⁶ × 3⁰ =
= 1 - 2⁶ ×1 =
= 1 - 2⁶ =
= 1-64 =
= -63