Question

1. 2/3 (5x+2) = 2(x+2)
2. 4x-1 per 3 + 6x+4 per 2 = 4x+3
3. 2y+4 per 4 - 4y-1 per 3 = 1

Answer 1

1. dikali 3 smua utk hilangkan pecahan 2(5x+2)=2*3(x+2) 10x+4=6×+12 4×=8 ×=2 2. dikali 6 smua utk hilangkan pecahan 2(4x-1)+3(6×+4)=6(4×+3) 8×-2+18×+12=24×+18 26×+10=24×+18 2×=8 ×=4 3. dikali 12 smu utk hilangkan pecahan 3(2y+4)+4(-4y-1)=1*12 6y+12-16y-4=12 -10y+8=12 -10y=-4 10y=4 y=4/10=0,4

Answer 2

1.))
10/3 x +4/3 = 4x+4
4/3-4 = 4x - 10/3 x
(4-12)/3 = (12-10)x/3
-8 = 2x (sama sama dicoret 3 nya)
-4 = x

2.))
(4x-1)/3 + (6x+4)/2 = 4x+3
(8x-2+18x+12)/6 = 4x+3
26x + 10 = 6 (4x +3)
26x-24x = 18 -10
2x = -8
x = -4

3.))
(2y+4)/4 - (4y-1)/3 = 1
(6y+12-16y+4)/12 = 1
-10y +16 = 12
16-12=10y
4/10 = y
2/5 = y