Question

Rozwiąż zadanie metodą podstawiania

2x+4/2 + y+1/3 =4

3(x+1) - 2(y-2)= y+4

Answer 1

2x + 4/2 + y + 1/3 = 4

3x +3 - 2y + 4 = y + 4

 

2x +y = 5/3

3x - 3y = 1

 

y = 5/3 - 2x

3x - 3(5/3 - 2x) = 1

 

y = 5/3 - 2x

3x - 5 + 6x = 1

 

y = 5/3 - 2x

9x = 6 I : 9

 

y = 5/3 - 2x

x = 2/3

 

y = 5/3 - 2 * 2/3

x = 2/3

 

y = 5/3 - 4/3

x = 2/3

 

y = 1/3

x = 2/3 

 

 

Answer 2

2x+4/2 + y+1/3 =4            |*6

3(x+1) - 2(y-2)= y+4

 

3(2x+4)+2(y+1)=4

3x+3-2y +4 = y+4

 

6x +12 + 2y +2 =4

3x-2y +7=  y+4

 

6x+2y =-10

3x-3y= -3    |*(-2)

 

6x+2y=-10

-6x+6y=6

____________________

8x=-4

x=-½

 

6*(-½)+2y=-10

-3+2y=-10

2y=-7

y=-3½

 

x=-½

y=-3½

 

 

 

 

Answer 3

2x+4/2 + y+1/3 =4

3(x+1) - 2(y-2)= y+4

 

2x+2+y+1/3=4

3x+3-2y+4=y+4

 

2x+y=4-2-1/3

3x-2y-y=4-3-4

 

2x+y=1i2/3

3x-3y=-3

 

y=-2x+1i2/3

3x-3y=-3

 

3x-3(-2x+1i2/3)=-3

3x+6x-5=-3

9x=-3+5

9x=2/:9

x=2/9

 

3(2/9)-3y=-3

2/3-3y=-3

-3y=-3-2/3

-3y=-3i2/3

-3y=-11/3   /:(-3)

y=11/9

y=1i2/9

 

wynik:

x=2/9

y=1i2/9