Question

Oblicz:

log[5](3x) - log[5](4y)

log[6]x - 2log[6](3y)

3log[2]5+1/2log[2]a

log[3]5 * log[3]27

log[121]6 * log[36]1/11

log[(pierwiastek z 3) / 3] 4 * log[32]9

Answer 1

log[5](3x/4y)

 

log[6](x)-log[6](3y)²=log[6](x/(3y)²)

 

log[2](5³)+log[2](a^½)=log[2](125·(√a))=log[2](125√a)

 

log[3](5)·log[3](3³)=log[3](5)·3log[3](3)=log[3](5)·3=3log[3](5)

log[11²](6)·log[6²](1/11)=(1/2)log[11](6)·(1/2)log[6](1/11)=(1/4)log[11](6)·log[6](11⁻¹) =(1/4)log[11](6)·(-1)log[6](11)=-(1/4)·1=-(1/4)

log[√3/3](4)·log[32](9) = log[√3/3](2²)·log[2⁵](3²)=2log[√3/3](2)·(1/5)·2log[2](3)=(4/5)log[√3/3](2)·log[2](3)=(4/5)log[√3/3](3)=(4/5)log[3^(-(1/2))](3)=(4/5)·(-2)log[3](3)=-8/5

 

mam nadzieję, że oto chodziło