Potrzebuje rozwiązać równanie:
1/3 * (3x-2)=2
3*(x-5)+7=x+1
Prosze o rozwiązanie;D
Daje NAJ....;P
a)x-2/3=2
x=2 i 2/3
b)3x-15+7=x+1
3x-x=15-7+1
2x=9
x=4,5
1.x-2/3=2 x=2+2/3 5(x/5-3)=315 5x/5-15=315/*5 5x-75=1575 5x=1500 x=300 3.2(x+7)=3(2x-5) 2x+14=6x-15 2x-6x=-15-14 -4x=-29 x=7,25 4.3(x-5)+7=x=1 3x-15+7=x+1 3x-x=1=15-7 2x=9 x=4,5
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a)x-2/3=2
x=2 i 2/3
b)3x-15+7=x+1
3x-x=15-7+1
2x=9
x=4,5
1.x-2/3=2
x=2+2/3
5(x/5-3)=315
5x/5-15=315/*5
5x-75=1575
5x=1500
x=300
3.2(x+7)=3(2x-5)
2x+14=6x-15
2x-6x=-15-14
-4x=-29
x=7,25
4.3(x-5)+7=x=1
3x-15+7=x+1 3x-x=1=15-7
2x=9 x=4,5