Question

Usuń niewymierność z mianownika: A. 3√11/√3+2 B.5+√3/√2-√3 Oblicz: A.-1/4*(7i1/3)+7i1/3:11/27 B-2/3-3,(08) Proszę o szybkie rozwiązanie. :)

Answer 1

A

3√11/(√3 + 2) = 3√11 * (√3 - 2)/(√3 + 2)(√3 - 2) = 3√11(√3 - 2)/3 - 4 = -3√11(√3 - 2)/1 = - 3√11(√3 - 2)

B

5 + √3/(√2 - √3) = (5 + √3) * (√2 + √3)/(√2 - √3)(√2 + √3) = (5 + √3)(√2 - √3)/- 1 = 

  = - (5 + √3)(√2 - √3)

 

A - 1/4 * (7 i 1/3) + 7 i 1/3 : 11/27 = - 1/4 * 22/3 + 22/3 : 27/11 = 

      = - 22/12 + 22/3 * 27/11 = - 22/12 * + 18 = - 1 i 10/12 + 18 =

      = - 1 i 10/12 + 17 i 12/12 = 16 i 2/12 = 16 i 1/6

B

- 2/3 - 3,08 = - 2/3 - 3 i 8/100 = - 2/3 - 3 i 2/25 = - 50/75 - 3 i 6/75 = - 3 i 56/75 =