Question

Potęga iloczynu, iloraz potęgi

Zad 7/22

a) (1/42)^3 : (-1/21)^3 - 100^3 * (-1/10)^3

b) (1,2)^3 : 12^3 -(0,6)^5 * (-1 2/3)^5

c) (-1 1/3) ^21 *( 0,75)^21 - (0,5)^0 : 2^0

Answer 1

a) (1/42)^3 : (-1/21)^3 - 100^3 * (-1/10)^3 = (1/42)³*(-21)³ - (-10)³ = (-1/2)³ - (-10)³ = -1/8+1000 = 999 7/8

 

b) (1,2)^3 : 12^3 -(0,6)^5 * (-1 2/3)^5 = 0,1³ - (6/10)⁵ * (-5/3)⁵ = 0,1 -(-30/30)⁵ = 0,1-(-1)⁵ = 0,1-(-1) = 0,1+1 = 1,1

 

 

c) (-1 1/3) ^21 *( 0,75)^21 - (0,5)^0 : 2^0 = (-4/3)²¹ * (3/4)²¹ -(0,25)⁰ = (-1)²¹ - 1 = -1-1 = -2