" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(∛2)¹⁵=32
Mamy kilka sposobów, m.in.
I. (√3)⁶=(3^(1/2))⁶=3^(6/2)=3³=3*3*3=27
II. (√3)⁶=√[3⁶]=√[3*3*3*3*3*3]=√[9*9*9]=√9*√9*√9=3*3*3=27
(∛2)¹⁵
I. (∛2)¹⁵=(2^(1/3))¹⁵=2^(15/3)=2⁵=2*2*2*2*2=32
II. (∛[2¹⁵])=∛[2*2*2*2*2*2*2*2*2*2*2*2*2*2*2]
=∛[8*8*8*8*8]=∛8*∛8*∛8*∛8*∛8=2*2*2*2*2=32