(3-√2)* (4√6-1)=
Proszę o rozwiązanie, bo ciagle mi się myli. Systemem każda przez każdą mnożona
(3-√2)* (4√6-1)=3*4√6-3*1-4*√[2*6]+√2=12√6-3-4√12+√2=12√6-4*2√3+√2-3=
=12√6-8√3+√2-3
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√12=√[4*3]=√4*√3=2√3
(3-√2)* (4√6-1)= 3*4√6 - 3*1 - √2*4√6 + √2 = 12√6 - 3 - 4√12 + √2 =
= 12√6-3 - 4√(4*3) + √2 = 12√6 - 3 - 8√3 + √2 = 12√6-8√3+√2-3
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(3-√2)* (4√6-1)=3*4√6-3*1-4*√[2*6]+√2=12√6-3-4√12+√2=12√6-4*2√3+√2-3=
=12√6-8√3+√2-3
-------------
√12=√[4*3]=√4*√3=2√3
(3-√2)* (4√6-1)= 3*4√6 - 3*1 - √2*4√6 + √2 = 12√6 - 3 - 4√12 + √2 =
= 12√6-3 - 4√(4*3) + √2 = 12√6 - 3 - 8√3 + √2 = 12√6-8√3+√2-3