Himpunan penyelesaian dari persamaann √3 tan (x - π/3) =1 untuk 0 ≤ x ≤ 2π adalah?
Suhartono√3 tan (x - π/3) = 1 tan (x - π/3) = 1/√3 tan (x - π/3) = tan π/6 x - π/3 = π/6 + k.π x = π/2 + k.π k = 0 maka x = π/2 k = 1 maka x = 3π/2 HP = {π/2. 3π/2}
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Fajriayi√3 tan (x - π/3) = 1 tan (x - π/3) = 1/√3 tan (x - π/3) = tan π/6 x - π/3 = π/6 + k.π x = π/2 + k.π k = 0 maka x = π/2 k = 1 maka x = 3π/2 HP = {π/2. 3π/2}
tan (x - π/3) = 1/√3
tan (x - π/3) = tan π/6
x - π/3 = π/6 + k.π
x = π/2 + k.π
k = 0 maka x = π/2
k = 1 maka x = 3π/2
HP = {π/2. 3π/2}
tan (x - π/3) = 1/√3
tan (x - π/3) = tan π/6
x - π/3 = π/6 + k.π
x = π/2 + k.π
k = 0 maka x = π/2
k = 1 maka x = 3π/2
HP = {π/2. 3π/2}