Question

Hasil penyelesaian persamaan berikut : 1/x+3 - 1/y+1 = 6
2/x+3 + 1/ 2y+2 = 4

Answer 1

Anggap saja,
1/(x+3) = a
1/(y+1) = b
Jadi,
a - b = 6 ..........menjadi 4a-4b = 24
2a + 1/2 b = 4...menjadi 4a+b = 8
Kurangi, didapat:
-5b = 12
b = -12/5
Substitusikan agar mendapat nilai a:
a-b = 6
a - 12/5 = 6
a = 6 + 12/5 = 42/5
Sehingga,
a = 42/5 dan b = -12/5
Karena,
1/(x+3) = a
1/(x+3) = 42/5
42(x+3) = 5
42x+126 = 5
42x = -121
x = -121/42
Dan,
1/(y+1) = b
1/(y+1) = -12/5
12(y+1) = -5
12y+12 = -5
12y = -17
y = -17/12

HP = {(x,y)|(-121/42 , -17/42)}