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2y (x-3) +z(x-3)
(x-3) (2y+z) ya se que es absurdo pero si hay la forma de factorizar
Resolvemos.
2xy - 6y + xz - 3z <=== agrupamos de dos en dos, sacamos factor común.
2y(x-3) +z(x - 3)
(x - 3) (2y + z)