Question

Tolong bantu ya,,, :) ni pr aku
intergral -1 sampai 3 dx/(2x+3)^2
,,,, makasih sebelumnya ^_^

Answer 1

Integral -1 sampai 3 (2x+3)^2 dx= integral -1 sampai 3 4x^2+12x=9 dx
= 4/3x^3+6x^2+9xI-1 sampai 3
=(4/3(3)^3 + 6.3^2+9.3)- ((4/3(-1)^3+6(-1)^2=9(-1))
=( 4/3.27+54+27)-(-4/3+6-9)
=117-4 1/4= 113 1/3