2x^3-5x^2-2x=0
rozwiaz równanie
x(2x^2-5x-2)=0
x=0 U 2x^2-5x-2=0
Δ=b^2-4ac=25+16=41 √Δ=√41
x1=(-b-√Δ)/2a=(5-√41)/4
x2=(-b+√Δ)/2a=(5+√41)/4
odp:
x=0 U x=(5-√41)/4 U x=(5+√41)/4
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2x^3-5x^2-2x=0
x(2x^2-5x-2)=0
x=0 U 2x^2-5x-2=0
Δ=b^2-4ac=25+16=41 √Δ=√41
x1=(-b-√Δ)/2a=(5-√41)/4
x2=(-b+√Δ)/2a=(5+√41)/4
odp:
x=0 U x=(5-√41)/4 U x=(5+√41)/4