Question

Rozwiąż równanie:
-1/2x^2=pierwiastek z 3 x

(x-3)(x+2)=(x+4)(2-x)-14

Answer 1

(x-3)(x+2)=(x+4)(2-x)-14
x²+2x-3x-6=2x-x²+8-4x-14
2x²-3x+4x=-6+6
2x²+x=0

-1/2x²=√3 x /*2x²
2√3 x³=-1
x³=-1/2√3
x³=-1√3/6
x=³√[(1-√3)/6]

Answer 2

(x-3)(x+2)=(x+4)(2-x)-14
2x+2x-3x-6=2x-x+8-4x-14
x-6=-3x-6/+6
x=-3x/+3x
4x=0/:4
x=0

-1/2x²=√3 x /*2x²
2√3 x³=-1
x³=-1/2√3
x³=-1√3/6
x=³√[(1-√3)/6]

Answer 3

1)

-1/2x² = √3*x
-1/2x²-√3x = 0
x(-1/2x-√3) = 0

x1 = 0

-1/2x-√3 = 0
-1/2x = √3 :(-1/2)
x = -2√3

x1 = 0
x2 = -2√3


2)

(x-3)(x+2)=(x+4)(2-x)-14
x²+2x-3x-6 = 2x-x²+8-4x-14
x²+x²-x-2x+4x = -6+6
2x²+x = 0
x(2x+1) = 0

x1 = 0

2x+1 = 0
2x = -1 |:2
x = -1/2

x1 = 0
x2 = -1/2