Question

Rozwiąż równanie:
-1/2x^2=pierwiastek z 3 razy x

(x-3)(x+2)=(x+4)(2-x)-14

Answer 1

(x-3)(x+2)=(x+4)(2-x)-14
x²+2x-3x-6=2x-x²+8-4x-14
x²+x²+2x-3x-2x+4x=6+8-14
2x²+x=0

Answer 2

1)

-1/2x² = √3*x
-1/2x²-√3x = 0
x(-1/2x-√3) = 0

x1 = 0

-1/2x-√3 = 0
-1/2x = √3 :(-1/2)
x = -2√3

x1 = 0
x2 = -2√3


2)

(x-3)(x+2)=(x+4)(2-x)-14
x²+2x-3x-6 = 2x-x²+8-4x-14
x²+x²-x-2x+4x = -6+6
2x²+x = 0
x(2x+1) = 0

x1 = 0

2x+1 = 0
2x = -1 |:2
x = -1/2

x1 = 0
x2 = -1/2