wykonaj działania odpowiedz podaj w najprostrzej postaci ^-do potęgi a) (x-4)(4+x)(x2+16) b) (1/2x^2+1)(1+1/4x^4)(1-1/2x^2) c) (x+y)^2+(x-y)^2 d) (x^2-1+x)(x-3) e) -5xy+3x(y-1)+2(x+3)(y+1)
karolinamarcin50
Odpowiedź:a) (x-4)(4+x)(x2+16)=(x-4)*(x+4)*(2x+16)=(x²-16)*(2x+16)=2x³+16x²-32x-256=2x³+16x²-32x-256
b) (1/2x^2+1)(1+1/4x^4)(1-1/2x^2)=(1+1/2*²)*(1-1/2*²)*(1+1/4*∧4)=(1-1/4*∧4)*(1+1/4*∧4)=1-1/16*∧8= 1-1/16x^8
c) (x+y)^2+(x-y)^2=x²+2xy+y²+(x-y)²=x²+2xy+y²+x²-2xy+y²=x²+y²+x²+y²=2x²+y²+y²=2x²+2y²=2x²+2y²
d) (x^2-1+x)(x-3)=x²*(x-3)-1(x-3)+x*(x-3)=x³-3x²-1(x-3)+x*(x-3)=x³-3x²-x+3+x*(x-3)=x³-3x²-x+3+x²-3x=x³-2x²-x+3-3x=x³-2x²-4x+3=x³-2x²-4x+3
e) -5xy+3x(y-1)+2(x+3)(y+1)=-5xy+3xy-3x+2(x+3)*(y+1)=-5xy-+3xy-3x+(2x+6)*(y+1)=-5xy-+3xy-3x+2xy+2x+6y+6=0-3x+2x+6y+6=0-x+6y+6=-x+6y+6=x+6y+6
2 votes Thanks 1
nnatalka0987
ale ja to potrzebuje jeszcze rozpisane