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fogog⁻¹oh = foh
foh(x)= [{fog} (g⁻¹oh)] =
foh(x) = [{fog}(3x-2)] = {3(3x-2) + 1} / {2(3x-2) +1}
foh(x)= (9x-5)/(6x-3)
(foh)⁻¹ (9x-5)/(6x-3) = x
(foh)⁻¹(2) = ...
(9x-5)/(6x-3) = 2
9x-5 = 2(6x-3)
9x-5 = 12x - 6
9x-12x = -6 + 5
-3x = -1
x = ¹/₃