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x + 2y + 2x = 3 , berarti 3x + 2y = 3
substitusikan nilai y , 3x + 2(5x + 4) = 3
3x + 10x + 8 = 3
13x = -5
x = -5/13
y = 5x + 4 , maka y = 5 × -5/13 + 4
y = 27/13
ambil persamaan terakhir . 2x + y + z = 3
2 (-5/13) + 27/13 + z = 3
z = 22/13
maka , x + y + z = -5/13 + 27/13 + 22/13
= 44/13
tanda / (per) artinya membentuk pecahan.
semoga bermanfaat ...
3x - y + 2x = -4
(=) x - y = -4
(=) x = y - 4
Kedua,
x + 2y + 2x = 3
(=) 3x + 2y = 3
(=) 3(y - 4) + 2y = 3
(=) 3y - 12 + 2y = 3
(=) y - 12 = 3
(=) y = 12 + 3 = 15
Karena sudah diketahui y = 15, substitusikan nilai y ke persamaan x = y - 4. Maka nilai x = 15 - 4 = 11.
Lalu, substitusikan nilai x dan y tadi ke persamaan 2x + y + z = 3
(=) 2(11) + 15 + z = 3
(=) 22 + 15 + z = 3
(=) 37 + z = 3
(=) z = 3 - 37 = -34
Maka hasil x + y + z = 11 + 15 + (-34) = -8
Semoga membantu.