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Verified answer
Bab Bangun RuangMatematika SMP Kelas VIII
tabung
A] volume akhir = volume awal x r² x t
= 942 x 2² x 1
= 942 x 4
= 3.768 cm³
B] volume akhir = volume awal x r² x t
= 942 x (1/2)² x 1
= 942 x 1/4 x 1
= 235,5 cm³
Tabung
A] Volume Akhir = Volume awal . r² . t
.................................= 942 . 2² . 1
.................................= 942 . 4
.................................= 3,768 cm^3
B] Volume Akhir = Volume Awal . r² . t
.................................= 942 . (1/2)² . 1
.................................= 942 . 1/4 . 1
.................................= 235,5 cm^3
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