Question

2x pangkat 2 di tambah 4x di kurangi 6 per 4x pangkat 2 di kurangi 36 di kali 4x pangkat 2 di tambah 4x ditambah 1 per 2x pangkat 2 dikurangi x dikurangi 1



pakai caranya

Answer 1

Jawab :

[(2x²+4x-6) / (4x²-36)] . [(4x²+4x+1) / (2x²-x-1)] = ?

[(2x²+4x-6) / (4x²-36)]

2x²+4x-6
2(x²+2x-3)
2(x+3)(x-1)

4x²-36
4(x²-9)
4(x-3)(x+3)

=[(2x²+4x-6) / (4x²-36)]
=2(x+3)(x-1) / 4(x-3)(x+3)
=(x-1) / 2(x-3)......................................................................(i)

[(4x²+4x+1) / (2x²-x-1)]

(4x²+4x+1)
(2x+1)(2x+1)

(2x²-x-1)
(2x+1)(x-1)

=[(4x²+4x+1) / (2x²-x-1)]
=[(2x+1)(2x+1)] / (2x+1)(x-1)
=(2x+1) / (x-1)...............................................................(ii)

=[(2x²+4x-6) / (4x²-36)] . [(4x²+4x+1) / (2x²-x-1)]
=(persamaan i) . (persamaan ii)
=[(x-1) / 2(x-3)] . [(2x+1) / (x-1)]
=(2x+1) / (2x-6)

Maaf ya, tak pecah-pecah nulisnya^^