2x ( do potęgi 3 ) - 3x ( do potęgi 2 ) - 4x +6
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2x³-3x²-4x+6=x²(2x-3)-2(2x-3)=(x²-2)(2x-3)=(x-√2)(x+√2)(2x-3)
x-√2=0
x=√2
x+√2=0
x=-√2
2x-3=0
2x=3/:2
x=3/2
x=1 i 1/2
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2x³-3x²-4x+6=x²(2x-3)-2(2x-3)=(x²-2)(2x-3)=(x-√2)(x+√2)(2x-3)
x-√2=0
x=√2
x+√2=0
x=-√2
2x-3=0
2x=3/:2
x=3/2
x=1 i 1/2