o ile to możliwe, dane równanie ogólne prostej zapisz w postaci kierunkowej: a) 1/2x-3y+8=0 b) 5x-3=0
a)-3y=-1/2x-8 y=-1/2x·(-1/3)-8/-3 y=1/6x+8/3 b)y=ax+b y=-5x+3
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a)-3y=-1/2x-8 y=-1/2x·(-1/3)-8/-3 y=1/6x+8/3 b)y=ax+b y=-5x+3