|2x-3|=|x+1|+x-4
3/2 -1
1. jeśli x ∈ (-oo, -1) to -(2x - 3) = -(x + 1) + x - 4
-2x + 3 = -x - 1 + x - 4
-2x + 3 = -5
-2x = -5 - 3
-2x = -8
x = 4 ∉ (-oo, -1)
2. jesli x ∈ <-1, 3/2> to -(2x - 3) = x + 1 + x - 4
-2x + 3 = 2x - 3
-2x - 2x = -3 - 3
-4x = -6
x = 3/2 ∈ <-1, 3/2>
3. jesli x ∈ (3/2, + oo) to 2x - 3 = x + 1 + x - 4
2x - 3 = 2x - 3
0 = 0
x ∈ R i x ∈ (3/2, +oo)
x ∈ (3/2, + oo)
odp. x ∈ <3/2, + oo)
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|2x-3|=|x+1|+x-4
3/2 -1
1. jeśli x ∈ (-oo, -1) to -(2x - 3) = -(x + 1) + x - 4
-2x + 3 = -x - 1 + x - 4
-2x + 3 = -5
-2x = -5 - 3
-2x = -8
x = 4 ∉ (-oo, -1)
2. jesli x ∈ <-1, 3/2> to -(2x - 3) = x + 1 + x - 4
-2x + 3 = 2x - 3
-2x - 2x = -3 - 3
-4x = -6
x = 3/2 ∈ <-1, 3/2>
3. jesli x ∈ (3/2, + oo) to 2x - 3 = x + 1 + x - 4
2x - 3 = 2x - 3
0 = 0
x ∈ R i x ∈ (3/2, +oo)
x ∈ (3/2, + oo)
odp. x ∈ <3/2, + oo)