Question

(2x-3)(2x+3)=(x+5)do kwadratu-9

2x(x-3)-(x+1)(x+2)=(2x-3)do kwadratu

(2x-1)do kwadratu-(4x+1)(4x-1)=4x(1-2x)

plis potrzebne na jutro!!!

Answer 1

(2x-3)(2x+3)=(x+5)do kwadratu-9
4x²-9=x²+10x+25-9

4x²-9=x²+10x+16

3x²-10x-25=0

Δ=100-4*3*(-25)=100+300=400

√Δ=20

x1=(10-20)/6=-10/6=-5/3

x2=(10+20)/6=30/6=5

2x(x-3)-(x+1)(x+2)=(2x-3)²

2x²-6x-(x²+2x+x+2)=4x²-12x+9

2x²-6x-x²-3x-2-4x²+12x-9=0

-3x²+3x-11=0

Δ=9-4*(-3)*(-11)=9-132=-123

Δ<0 brak pierwiastkow

(2x-1)²-(4x+1)(4x-1)=4x(1-2x)

4x²-4x+1-(16x²-1)=4x-8x²

4x²-4x+1-16x²+1-4x+8x²=0

-4x²-8x+2=0 //:2

-2x²-4x+1=0

Δ=16-4*(-2)*1=16+8= 24

√Δ=2√6

x1=(4-2√6)/-4=-1+√6/2

x2=(4+2√6)/-4=-1-√6/2

 

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